derivative of (x^2-16/(x+4))

解答

\frac{d}{d x} (\frac{x ^{2} - 16}{x + 4})

1

求解步骤

\frac{d}{d x} (\frac{x ^{2} - 16}{x + 4})

化简

\frac{x ^{2} - 16}{x + 4} : x - 4

= \frac{d}{d x} (x - 4)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (4)

\frac{d x}{d x} = 1

\frac{d}{d x} (4) = 0

= 1 - 0

化简

= 1

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