What is the integral from 0 to ln(2) of se^s ?

The integral from 0 to ln(2) of se^s is 2ln(2)-1

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integral from 0 to ln(2) of se^s

\int_{0}^{l n (2)} s e^{s} d s

2 ln (2) - 1

Decimal

0.38629 \dots

Solution steps

\int_{0}^{l n (2)} s e^{s} d s

Apply Integration By Parts

: [e^{s} s - \int e^{s} d s]_{0}^{l n (2)}

= [e^{s} s - \int e^{s} d s]_{0}^{l n (2)}

\int e^{s} d s = e^{s}

= [e^{s} s - e^{s}]_{0}^{l n (2)}

Compute the boundaries:

2 ln (2) - 1

= 2 ln (2) - 1

\frac{\partial}{\partial x} (\frac{2}{2 x + y})

x \to - 2 lim (- x^{2} + 4 x - 6)

f (x) = x^{2} + 1, (- 2, 5)

\int \frac{x}{( 1 + x ^{3} )} d x

x \to 0 + lim (sin (x))

What is the integral from 0 to ln(2) of se^s ?
The integral from 0 to ln(2) of se^s is 2ln(2)-1