What is the solution for y^'=(x^2)/(y(1+x^3)) ?

The solution for y^'=(x^2)/(y(1+x^3)) is y=sqrt((2ln(1+x^3)+c_{1))/3},y=-sqrt((2ln(1+x^3)+c_{1))/3}

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y^'=(x^2)/(y(1+x^3))

y^{^{'}} = \frac{x ^{2}}{y ( 1 + x ^{3} )}

y = \frac{2 ln ( 1 + x ^{3} ) + c _{1}}{3}, y = - \frac{2 ln ( 1 + x ^{3} ) + c _{1}}{3}

Solution steps

y^{'} (x) = \frac{x ^{2}}{y ( 1 + x ^{3} )}

Solve separable ODE:

y = \frac{2 ln ( 1 + x ^{3} ) + c _{1}}{3}, y = - \frac{2 ln ( 1 + x ^{3} ) + c _{1}}{3}

y = \frac{2 ln ( 1 + x ^{3} ) + c _{1}}{3}, y = - \frac{2 ln ( 1 + x ^{3} ) + c _{1}}{3}

\frac{d}{d x} (2^{c o t (5 x)})

\frac{d}{d x} (\frac{1}{x ( ln ( x ) ) ^{2}})

\int \frac{( x - 2 ) 1 - x ^{2} + x}{1 - x ^{2}} d x

\int x sec^{2} (5 x) d x

y^{^{''}} + 4 y = - 2

What is the solution for y^'=(x^2)/(y(1+x^3)) ?
The solution for y^'=(x^2)/(y(1+x^3)) is y=sqrt((2ln(1+x^3)+c_{1))/3},y=-sqrt((2ln(1+x^3)+c_{1))/3}