What is the tangent of f(x)= 5/(sqrt(x)),(1,5) ?

The tangent of f(x)= 5/(sqrt(x)),(1,5) is y=-5/2 x+15/2

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tangent of f(x)= 5/(sqrt(x)),(1,5)

tangent of

f (x) = \frac{5}{x}, (1, 5)

y = - \frac{5}{2} x + \frac{15}{2}

Solution steps

Find the slope of

f (x) = \frac{5}{x} : \frac{df ( x )}{d x} = - \frac{5}{2 x ^{\frac{3}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{5}{2}

Find the line with slope m=

- \frac{5}{2}

and passing through

(1, 5) : y = - \frac{5}{2} x + \frac{15}{2}

y = - \frac{5}{2} x + \frac{15}{2}

\frac{d}{d x} ((x^{2} + x^{3})^{4})

\frac{\partial}{\partial x} (x \cdot y^{2} \cdot e^{z})

y = cos^{3} (π t - 16)

f (x) = x^{4} + 2 x^{2} - x, (1, 2)

\frac{d}{d x} (x, x^{2} - y, x + y^{2})

What is the tangent of f(x)= 5/(sqrt(x)),(1,5) ?
The tangent of f(x)= 5/(sqrt(x)),(1,5) is y=-5/2 x+15/2