(2y^2+4x^2)dx=xydy

Lösung

(2 y^{2} + 4 x^{2}) d x = x y d y

y = x - 4 + c_{1} x^{2}, y = - x - 4 + c_{1} x^{2}

Schritte zur Lösung

(2 y^{2} + 4 x^{2}) d x = x y d y

Solve Bernoulli ODE:

y = x - 4 + c_{1} x^{2}, y = - x - 4 + c_{1} x^{2}

y = x - 4 + c_{1} x^{2}, y = - x - 4 + c_{1} x^{2}

x (\frac{d y}{d x}) + y = e^{x}

x \to 3 lim (- \frac{x - 4}{x - 3})

d er i v a t i v e t^{2} - \frac{1}{t ^{3}}

\frac{\partial}{\partial x} (\frac{y - 3 x}{z})

x \to 1 - lim (2 x + 3)