y^'=y(1/x-y)

Lösung

y^{^{'}} = y (\frac{1}{x} - y)

y = \frac{2 x}{x ^{2} + c _{1}}

Schritte zur Lösung

y^{'} (x) = y (\frac{1}{x} - y)

Solve Bernoulli ODE:

y = \frac{2 x}{x ^{2} + c _{1}}

y = \frac{2 x}{x ^{2} + c _{1}}

a re a y = x^{2} - 4 x - 5, y = 2 x - 5

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