What is the tangent of x^2+xy+2y^2=28,(-5,3) ?

The tangent of x^2+xy+2y^2=28,(-5,3) is y=x+8

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tangent of x^2+xy+2y^2=28,(-5,3)

tangent of

x^{2} + x y + 2 y^{2} = 28, (- 5, 3)

y = x + 8

Solution steps

Find the slope of

x^{2} + x y + 2 y^{2} = 28 : \frac{d y}{d x} = \frac{- 2 x - y}{x + 4 y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(- 5, 3) : y = x + 8

y = x + 8

\frac{100}{s ( s ^{2} + 25 )}

x \to 2 - lim (2 x - 4)

\frac{d y}{d x} + 3 x^{2} y = x^{2}

x \to 0 lim (\frac{cos ( x )}{2})

\int s d s

What is the tangent of x^2+xy+2y^2=28,(-5,3) ?
The tangent of x^2+xy+2y^2=28,(-5,3) is y=x+8