What is the derivative of sin(xdx) ?

The derivative of sin(xdx) is d(xcos(x)+sin(x))

What is the first derivative of sin(xdx) ?

The first derivative of sin(xdx) is d(xcos(x)+sin(x))

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\frac{d}{d x} (sin (x) d x)

d (x cos (x) + sin (x))

Solution steps

\frac{d}{d x} (sin (x) d x)

Treat

d

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= d \frac{d}{d x} (sin (x) x)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sin (x), g = x

= d (\frac{d}{d x} (sin (x)) x + \frac{d x}{d x} sin (x))

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d x}{d x} = 1

= d (cos (x) x + 1 \cdot sin (x))

Simplify

= d (x cos (x) + sin (x))

\int x 3 x - 2 d x

\frac{d}{d x} ((3 x)^{l n (3 x)})

\frac{d r}{d t} = - 2 t r, r (0) = 2

\int sin^{- \frac{3}{2}} (x) cos^{3} (x) d x

x \to - 1 lim (2 x^{2} - 5 x + 3)

What is the derivative of sin(xdx) ?
The derivative of sin(xdx) is d(xcos(x)+sin(x))
What is the first derivative of sin(xdx) ?
The first derivative of sin(xdx) is d(xcos(x)+sin(x))