y^{''}+2y^'+y=0,y(0)=4,y^'(0)=-3

Lösung

y^{^{''}} + 2 y^{^{'}} + y = 0, y (0) = 4, y^{^{'}} (0) = - 3

y = 4 e^{- t} + e^{- t} t

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) + y = 0

Solve linear ODE:

y = 4 e^{- t} + e^{- t} t

y = 4 e^{- t} + e^{- t} t

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