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Popular Calculus >

integral from-5 to 1 of (2x+6)

Solution

\int_{- 5}^{1} (2 x + 6) d x

Solution

12

Solution steps

\int_{- 5}^{1} 2 x + 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 5}^{1} 2 x d x + \int_{- 5}^{1} 6 d x

\int_{- 5}^{1} 2 x d x = - 24

\int_{- 5}^{1} 6 d x = 36

= - 24 + 36

Simplify

= 12

Graph

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d er i v a t i v e \frac{7}{t}

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l a pl a ce t r an s f or m \frac{1}{2} t^{2}

area y=2x-1,x=2,x=5,y=0

a re a y = 2 x - 1, x = 2, x = 5, y = 0

derivative of-1/3 ln((tan(x/2-3)/3))

\frac{d}{d x} (- \frac{1}{3} ln (\frac{tan ( \frac{x}{2} ) - 3}{3}))

y^{''}+6y^'+8y=130cos(3t)

y^{^{''}} + 6 y^{^{'}} + 8 y = 130 cos (3 t)

Frequently Asked Questions (FAQ)

What is the integral from-5 to 1 of (2x+6) ?
The integral from-5 to 1 of (2x+6) is 12