integral of (2t^5)/5-(2t^2)/5-(2t)/5

Lösung

\int \frac{2 t ^{5}}{5} - \frac{2 t ^{2}}{5} - \frac{2 t}{5} d t

\frac{t ^{6}}{15} - \frac{2 t ^{3}}{15} - \frac{t ^{2}}{5} + C

Schritte zur Lösung

\int \frac{2 t ^{5}}{5} - \frac{2 t ^{2}}{5} - \frac{2 t}{5} d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2 t ^{5}}{5} d t - \int \frac{2 t ^{2}}{5} d t - \int \frac{2 t}{5} d t

\int \frac{2 t ^{5}}{5} d t = \frac{t ^{6}}{15}

\int \frac{2 t ^{2}}{5} d t = \frac{2 t ^{3}}{15}

\int \frac{2 t}{5} d t = \frac{t ^{2}}{5}

= \frac{t ^{6}}{15} - \frac{2 t ^{3}}{15} - \frac{t ^{2}}{5}

Füge eine Konstante zur Lösung hinzu

= \frac{t ^{6}}{15} - \frac{2 t ^{3}}{15} - \frac{t ^{2}}{5} + C

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