derivative-0.6t^2+30t

Lösung

ableitung von

- 0.6 t^{2} + 30 t

- 1.2 t + 30

Schritte zur Lösung

\frac{d}{d t} (- 0.6 t^{2} + 30 t)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (0.6 t^{2}) + \frac{d}{d t} (30 t)

\frac{d}{d t} (0.6 t^{2}) = 1.2 t

\frac{d}{d t} (30 t) = 30

= - 1.2 t + 30

\int_{0}^{5} π (- \frac{3}{5} x + 3)^{2} d x

d er i v a t i v e \frac{t ^{3} + 3 t}{t ^{2} - 4 t + 3}

\int \frac{7}{x ( x - 7 ) ^{2}} d x

\frac{d}{d x} ((x - 100)^{3} + (x - 100)^{2} + 500)

\int 1 - y^{2} d y