derivative of 48x(4x^2+9^5)

Lösung

\frac{d}{d x} (48 x (4 x^{2} + 9)^{5})

48 ((4 x^{2} + 9)^{5} + 40 x^{2} (4 x^{2} + 9)^{4})

Schritte zur Lösung

\frac{d}{d x} (48 x (4 x^{2} + 9)^{5})

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 48 \frac{d}{d x} (x (4 x^{2} + 9)^{5})

Wende die Produktregel an:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = (4 x^{2} + 9)^{5}

= 48 (\frac{d x}{d x} (4 x^{2} + 9)^{5} + \frac{d}{d x} ((4 x^{2} + 9)^{5}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} ((4 x^{2} + 9)^{5}) = 40 x (4 x^{2} + 9)^{4}

= 48 (1 \cdot (4 x^{2} + 9)^{5} + 40 x (4 x^{2} + 9)^{4} x)

Vereinfache

48 (1 \cdot (4 x^{2} + 9)^{5} + 40 x (4 x^{2} + 9)^{4} x) : 48 ((4 x^{2} + 9)^{5} + 40 x^{2} (4 x^{2} + 9)^{4})

= 48 ((4 x^{2} + 9)^{5} + 40 x^{2} (4 x^{2} + 9)^{4})

\int \frac{x ^{2} + 4 x - 5}{x ^{3} - 1} d x

d er i v a t i v e f (x) = 1680 (2 x + 5)^{4}

d er i v a t i v e x arcsin (x) + 1 - x^{2}

\frac{\partial}{\partial x} (x - ln (x + 1))

d er i v a t i v e X^{2}