derivative f(x)=2x^2-1

Lösung

ableitung von

f (x) = 2 x^{2} - 1

4 x

Schritte zur Lösung

\frac{d}{d x} (2 x^{2} - 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (1) = 0

= 4 x - 0

Vereinfache

= 4 x

x \to 0 + lim ((1 + x^{2})^{\frac{1}{x}})

y^{^{''}} + 16 y = cos (4 x) + sin (4 x)

\int + \frac{x ^{2}}{1 - 2 x ^{3}} d x

n = 0 \sum \infty \frac{( n - 1 )}{n}

\int_{1}^{3} (x^{2} - 4 x + 3) d x