What is the derivative of 4+8x-5x^2 ?

The derivative of 4+8x-5x^2 is -10x+8

What is the first derivative of 4+8x-5x^2 ?

The first derivative of 4+8x-5x^2 is -10x+8

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\frac{d}{d x} (4 + 8 x - 5 x^{2})

- 10 x + 8

Solution steps

\frac{d}{d x} (4 + 8 x - 5 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4) + \frac{d}{d x} (8 x) - \frac{d}{d x} (5 x^{2})

\frac{d}{d x} (4) = 0

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (5 x^{2}) = 10 x

= 0 + 8 - 10 x

Simplify

= - 10 x + 8

\int 8 e^{4 y} d y

\frac{1}{( s ^{2} + 3 )}

4 - x^{2}, x

- 2 y^{^{''}} + 2 y^{^{'}} = 0, y (1) = - 2, y^{^{'}} (- 2) = 3

x \to 0 lim (\frac{x}{3 + x - 3})

What is the derivative of 4+8x-5x^2 ?
The derivative of 4+8x-5x^2 is -10x+8
What is the first derivative of 4+8x-5x^2 ?
The first derivative of 4+8x-5x^2 is -10x+8