What is the derivative of ln(x+9) ?

The derivative of ln(x+9) is 1/(x+9)

What is the first derivative of ln(x+9) ?

The first derivative of ln(x+9) is 1/(x+9)

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derivative of

ln (x + 9)

\frac{1}{x + 9}

Solution steps

\frac{d}{d x} (ln (x + 9))

Apply the chain rule:

\frac{1}{x + 9} \frac{d}{d x} (x + 9)

= \frac{1}{x + 9} \frac{d}{d x} (x + 9)

\frac{d}{d x} (x + 9) = 1

= \frac{1}{x + 9} \cdot 1

Simplify

= \frac{1}{x + 9}

t \to 0 lim (e^{- 3 t})

\frac{d}{d x} (a x^{2} e^{4 x})

a re a y = x, y = \frac{6.75 x}{x ^{2} + 1}

d er i v a t i v e f (x) = (x + 2) e^{- x}

\int \frac{x}{27 + x ^{2}} d x

What is the derivative of ln(x+9) ?
The derivative of ln(x+9) is 1/(x+9)
What is the first derivative of ln(x+9) ?
The first derivative of ln(x+9) is 1/(x+9)