y(1+x^2)y^'-x(1+y^2)=0

Lösung

y (1 + x^{2}) y^{^{'}} - x (1 + y^{2}) = 0

y = e^{2 c_{1}} + e^{2 c_{1}} x^{2} - 1, y = - e^{2 c_{1}} + e^{2 c_{1}} x^{2} - 1

Schritte zur Lösung

y (1 + x^{2}) y^{'} (x) - x (1 + y^{2}) = 0

Solve separable ODE:

y = e^{2 c_{1}} + e^{2 c_{1}} x^{2} - 1, y = - e^{2 c_{1}} + e^{2 c_{1}} x^{2} - 1

y = e^{2 c_{1}} + e^{2 c_{1}} x^{2} - 1, y = - e^{2 c_{1}} + e^{2 c_{1}} x^{2} - 1

d er i v a t i v e y = 12

x \to 0 lim (2 x - 7)

\frac{\partial}{\partial x} (3 - x^{4} + 2 x^{2} - y^{2})

\int_{- \frac{π}{6}}^{0} 2 sec^{3} (x) d x

\frac{\partial}{\partial y} (x^{a} y^{b} z^{c})