(\partial)/(\partial y)(-2+e^{-x}cos(y))

解答

\frac{\partial}{\partial y} (- 2 + e^{- x} cos (y))

- e^{- x} sin (y)

求解步骤

\frac{\partial}{\partial y} (- 2 + e^{- x} cos (y))

将

x

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial y} (2) + \frac{\partial}{\partial y} (e^{- x} cos (y))

\frac{\partial}{\partial y} (2) = 0

\frac{\partial}{\partial y} (e^{- x} cos (y)) = - e^{- x} sin (y)

= - 0 - e^{- x} sin (y)

化简

= - e^{- x} sin (y)

t an g e n t \frac{2 x}{( x ^{2} + 1 )}

x \to - 1 lim (2 x^{2} + 3 x + 1)

\int 21 y d y

y^{^{''}} - \frac{2}{r} y^{^{'}} + \frac{2}{r ^{2}} y = 0, y (1) = 1, y (2) = 0

\int 12 x^{2} - 48 x + 36 d x