derivative of ln(2x+4)

Lösung

\frac{d}{d x} (ln (2 x + 4))

\frac{1}{x + 2}

Schritte zur Lösung

\frac{d}{d x} (ln (2 x + 4))

Wende die Kettenregel an:

\frac{1}{2 x + 4} \frac{d}{d x} (2 x + 4)

= \frac{1}{2 x + 4} \frac{d}{d x} (2 x + 4)

\frac{d}{d x} (2 x + 4) = 2

= \frac{1}{2 x + 4} \cdot 2

Vereinfache

\frac{1}{2 x + 4} \cdot 2 : \frac{1}{x + 2}

= \frac{1}{x + 2}

\int ln (u) d u

x \to \infty lim (\frac{x ^{2} + 3}{3 x ^{2} + 1})

\int \frac{2 x ^{3} + x ^{2} - 5}{x - 1} d x

(x^{2} + 1) y^{^{'}} + 5 x (y - 1) = 0, y (0) = 9

n = 0 \sum \infty q^{n}