(\partial)/(\partial x)(8x^2-7x+4)

解答

\frac{\partial}{\partial x} (8 x^{2} - 7 x + 4)

16 x - 7

求解步骤

\frac{\partial}{\partial x} (8 x^{2} - 7 x + 4)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (8 x^{2}) - \frac{\partial}{\partial x} (7 x) + \frac{\partial}{\partial x} (4)

\frac{\partial}{\partial x} (8 x^{2}) = 16 x

\frac{\partial}{\partial x} (7 x) = 7

\frac{\partial}{\partial x} (4) = 0

= 16 x - 7 + 0

化简

= 16 x - 7

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