derivative f(-1)=x^2+2-1

Lösung

ableitung von

f (- 1) = x^{2} + 2 - 1

2 x

Schritte zur Lösung

\frac{d}{d x} (x^{2} + 2 - 1)

Vereinfache

x^{2} + 2 - 1 : x^{2} + 1

= \frac{d}{d x} (x^{2} + 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= 2 x + 0

Vereinfache

= 2 x

d er i v a t i v e f (x) = \frac{1}{2 x + 3}

\int (x^{3} + 2 x)^{5} (6 x^{2} + 4) d x

\frac{d}{d x} (ln (\frac{x}{2 e}))

t an g e n t f (x) = x^{2} + 9, (- 2, 13)

\int_{0}^{2} \frac{1}{x - 1} d x