What is the derivative of f(x)=((x^2-3x))/2 ?

The derivative of f(x)=((x^2-3x))/2 is x-3/2

What is the first derivative of f(x)=((x^2-3x))/2 ?

The first derivative of f(x)=((x^2-3x))/2 is x-3/2

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derivative of

f (x) = \frac{( x ^{2} - 3 x )}{2}

x - \frac{3}{2}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 3 x}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (x^{2} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

= \frac{1}{2} (2 x - 3)

Simplify

\frac{1}{2} (2 x - 3) : x - \frac{3}{2}

= x - \frac{3}{2}

\frac{\partial}{\partial x} (x^{2} + y^{2} + x y + 3)

\frac{d y}{d x} = \frac{x ^{2} - 9}{x}

\int_{0}^{3} x e^{- 4 x} d x

y = 5 e^{x} + 7 ln (x)

\frac{\partial}{\partial x} (1 + x^{3} + x^{4})

What is the derivative of f(x)=((x^2-3x))/2 ?
The derivative of f(x)=((x^2-3x))/2 is x-3/2
What is the first derivative of f(x)=((x^2-3x))/2 ?
The first derivative of f(x)=((x^2-3x))/2 is x-3/2