(\partial)/(\partial x)((y+cx),(x+k))

解答

\frac{\partial}{\partial x} ((y + c x), (x + k))

(, (c (x + k) + 1 \cdot (y + c x)))

求解步骤

\frac{\partial}{\partial x} ((y + c x), (x + k))

将

c, k, y

视为常数

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= (, \frac{\partial}{\partial x} ((y + c x) (x + k)))

使用微分乘法定则:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = y + c x, g = x + k

= (, (\frac{\partial}{\partial x} (y + c x) (x + k) + \frac{\partial}{\partial x} (x + k) (y + c x)))

\frac{\partial}{\partial x} (y + c x) = c

\frac{\partial}{\partial x} (x + k) = 1

= (, (c (x + k) + 1 \cdot (y + c x)))

x \to \infty lim (\frac{1}{6 x})

\frac{d}{d x} ((- x^{2} + 9)^{2})

\frac{\partial}{\partial v} (x^{5} v^{2} + 2 y^{3} u - 3)

\int 2^{\frac{x}{2}} d x

x \cdot \frac{d y}{d x} = 2 x e^{x} - y + 6 x^{2}