csc(y)dx+sec(2)(x)dy=0

解答

csc (y) d x + sec (2) (x) d y = 0

y = arccos (cos (2) ln (x) - c_{1}) + 2 πn, y = - arccos (cos (2) ln (x) - c_{1}) + 2 πn

求解步骤

csc (y) d x + sec (2) (x) d y = 0

求解可分离方程:

y = arccos (cos (2) ln (x) - c_{1}) + 2 πn, y = - arccos (cos (2) ln (x) - c_{1}) + 2 πn

y = arccos (cos (2) ln (x) - c_{1}) + 2 πn, y = - arccos (cos (2) ln (x) - c_{1}) + 2 πn

\frac{d ^{2}}{d x ^{2}} (\frac{6 x ^{5}}{5} - 7 x)

\int (sin (y) cos (x)) d x

y^{^{'}} = y^{2} e^{(2 x)}

\frac{d}{d x} (4^{x} ln (x))

d er i v a t i v e f (x) = 5 cos^{2} (π x)