(dy)/(dx)=(2x)/(x+2)

Lösung

\frac{d y}{d x} = \frac{2 x}{x + 2}

y = 2 (x + 2 - 2 ln (x + 2)) + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = \frac{2 x}{x + 2}

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = \frac{2 x}{x + 2}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int \frac{2 x}{x + 2} d x

\int \frac{2 x}{x + 2} d x = 2 (x + 2 - 2 ln (x + 2)) + c_{1}

y = 2 (x + 2 - 2 ln (x + 2)) + c_{1}

\int \frac{12}{x ^{5}} d x

n \to \infty lim (e^{3 n^{2}})

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