What is the derivative of 3x+2xln(x) ?

The derivative of 3x+2xln(x) is 2ln(x)+5

What is the first derivative of 3x+2xln(x) ?

The first derivative of 3x+2xln(x) is 2ln(x)+5

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\frac{d}{d x} (3 x + 2 x ln (x))

2 ln (x) + 5

Solution steps

\frac{d}{d x} (3 x + 2 x ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (2 x ln (x))

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2 x ln (x)) = 2 (ln (x) + 1)

= 3 + 2 (ln (x) + 1)

Simplify

3 + 2 (ln (x) + 1) : 2 ln (x) + 5

= 2 ln (x) + 5

\frac{\partial}{\partial y} (e^{- 2 x} cos (2 y))

\int (1 - x)^{4} d x

\frac{5 n ^{3} - 3 n + 1}{2 n - n ^{4}}

- x^{2} + 3 x + a

x \to 0 lim (2 x^{2} - 2 x - 12)

What is the derivative of 3x+2xln(x) ?
The derivative of 3x+2xln(x) is 2ln(x)+5
What is the first derivative of 3x+2xln(x) ?
The first derivative of 3x+2xln(x) is 2ln(x)+5