derivative f(x)=cos(3x+2)-7x

Lösung

ableitung von

f (x) = cos (3 x + 2) - 7 x

- sin (3 x + 2) \cdot 3 - 7

Schritte zur Lösung

\frac{d}{d x} (cos (3 x + 2) - 7 x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (cos (3 x + 2)) - \frac{d}{d x} (7 x)

\frac{d}{d x} (cos (3 x + 2)) = - sin (3 x + 2) \cdot 3

\frac{d}{d x} (7 x) = 7

= - sin (3 x + 2) \cdot 3 - 7

d er i v a t i v e \frac{x sec ^{2} ( x ) - tan ( x )}{4 x ^{2}}

\frac{d y}{d x} = 3 x^{2} + 2 x - 7

\frac{\partial}{\partial x} (\frac{x ^{2} y ^{2}}{2})

n = 1 \sum \infty n^{- s i n (2)}

(cos^{2} (θ))^{^{'}}