(dy)/(dx)=((x-4))/(y-6)

解答

\frac{d y}{d x} = \frac{( x - 4 )}{y - 6}

y = 6 + x^{2} - 8 x + c_{1} + 36, y = 6 - x^{2} - 8 x + c_{1} + 36

求解步骤

\frac{d y}{d x} = \frac{( x - 4 )}{y - 6}

求解可分离方程:

y = 6 + x^{2} - 8 x + c_{1} + 36, y = 6 - x^{2} - 8 x + c_{1} + 36

y = 6 + x^{2} - 8 x + c_{1} + 36, y = 6 - x^{2} - 8 x + c_{1} + 36

a re a y = 10 + 9 x - x^{2}, y = - 3 x + 46, [6, 15 + \frac{1}{3}]

t y^{^{'}} = t^{3} + 7 t^{3} y

\frac{d}{d x} (tan (x) + cot (x))

\int \frac{9 + x}{x} d x

y^{^{'}} = - \frac{4 x}{y}