What is the tangent of sqrt(5x+4),\at x=9 ?

The tangent of sqrt(5x+4),\at x=9 is y= 5/14 x+53/14

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tangent of sqrt(5x+4),\at x=9

tangent of

5 x + 4, at x = 9

y = \frac{5}{14} x + \frac{53}{14}

Solution steps

Find the tangent point:

(9, 7)

Find the slope of

y = 5 x + 4 : \frac{d y}{d x} = \frac{5}{2 5 x + 4}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{5}{14}

Find the line with slope m=

\frac{5}{14}

and passing through

(9, 7) : y = \frac{5}{14} x + \frac{53}{14}

y = \frac{5}{14} x + \frac{53}{14}

x \to - 2 lim (4 x^{2} - 3)

f (x) = 2 - x^{2}

x \to 1 lim (f (x) (x^{2} - 2 x))

\frac{d}{d x} (3 x - ln (3 x + 1))

a re a 2 x, x

What is the tangent of sqrt(5x+4),\at x=9 ?
The tangent of sqrt(5x+4),\at x=9 is y= 5/14 x+53/14