integral from 2 to 3 of (4+2x)^2

Lösung

\int_{2}^{3} (4 + 2 x)^{2} d x

\frac{244}{3}

Dezimale

81.33333 \dots

Schritte zur Lösung

\int_{2}^{3} (4 + 2 x)^{2} d x

Multipliziere aus

(4 + 2 x)^{2} : 16 + 16 x + 4 x^{2}

= \int_{2}^{3} 16 + 16 x + 4 x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{3} 16 d x + \int_{2}^{3} 16 x d x + \int_{2}^{3} 4 x^{2} d x

\int_{2}^{3} 16 d x = 16

\int_{2}^{3} 16 x d x = 40

\int_{2}^{3} 4 x^{2} d x = \frac{76}{3}

= 16 + 40 + \frac{76}{3}

Vereinfache

16 + 40 + \frac{76}{3} : \frac{244}{3}

= \frac{244}{3}

\frac{\partial}{\partial x} (x^{9} y z^{2} + 9 yz)

\int \frac{1}{1 + 2 u} d u

\int (3 x^{2} - 4 x + 7) d x

d er i v a t i v e f (x) = (\frac{x ^{2} + 4}{x ^{2} - 4})^{4}

\frac{d y}{d x} = \frac{( x y + 3 x - y - 3 )}{( x y - 2 x + 4 y - 8 )}