(d^2y)/(dx^2)+y=1+x

Lösung

\frac{d ^{2} y}{d x ^{2}} + y = 1 + x

y = c_{1} cos (x) + c_{2} sin (x) + x + 1

Schritte zur Lösung

\frac{d ^{2} y}{d x ^{2}} + y = 1 + x

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + x + 1

y = c_{1} cos (x) + c_{2} sin (x) + x + 1

\int (4 x^{3} - 9 x^{2} + 7 x) e^{- x} d x

\frac{d}{d x} (7 x - 2)

(x + y)^{2} d x + (2 x y + x^{2} - 2) d y = 0, y (1) = 1

d er i v a t i v e f (x) = (x + 5)^{\frac{2}{3}} (2 x^{2} - 1)^{3}

\int \frac{1}{1 + e ^{3 x}} d x