What is the first derivative of y=3x-5 ?

The first derivative of y=3x-5 is 3

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derivative of y=3x-5

derivative of

y = 3 x - 5

3

Solution steps

\frac{d}{d x} (3 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (5)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (5) = 0

= 3 - 0

Simplify

= 3

\frac{\partial}{\partial y} (ln (2 x + y))

\frac{d}{d x} ((x^{2} + y^{2}) e^{x^{2} + y^{2}})

t an g e n t f (x) = \frac{6 x}{x ^{2} + 1}, at x = - 1

\frac{\partial}{\partial x} (- y sin (x ln (y) ln (y)))

\int \frac{1}{x ^{2} - 6 x - 16} d x