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normal y=x^2-5x,(7,14)

解答

法线

y = x^{2} - 5 x, (7, 14)

解答

y = - \frac{1}{9} x + \frac{133}{9}

求解步骤

计算

y = x^{2} - 5 x

的斜率:

\frac{d y}{d x} = 2 x - 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 9

计算垂线的斜率:

m_{p} = - \frac{1}{9}

找到斜率 m=

- \frac{1}{9}

且穿过

(7, 14)

的直线:

y = - \frac{1}{9} x + \frac{133}{9}

y = - \frac{1}{9} x + \frac{133}{9}

作图

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