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Beliebt Rechnen >

inverselaplace (e^{-7s})/((s^2-25))

Lösung

inverse laplace transformation

\frac{e ^{- 7 s}}{( s ^{2} - 25 )}

Lösung

H (t - 7) \frac{1}{5} sinh (5 (t - 7))

Schritte zur Lösung

L^{- 1} {\frac{e ^{- 7 s}}{( s ^{2} - 25 )}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {e^{- a s} F (s)} = H (t - a) f (t - a)

Wo

H (t)

Heaviside (Schritt) Funktion ist

= H (t - 7) L^{- 1} {\frac{1}{s ^{2} - 25}} (t - 7)

L^{- 1} {\frac{1}{s ^{2} - 25}} : \frac{1}{5} sinh (5 t)

= H (t - 7) \frac{1}{5} sinh (5 (t - 7))

Beliebte Beispiele

d/(da)(cos(a)*sin(a))

\frac{d}{d a} (cos (a) \cdot sin (a))

integral of 6sin^2(xco)s^2x

\int 6 sin^{2} (x co) s^{2} x d x

derivative of 6/((x-1^2))

\frac{d}{d x} (\frac{6}{( x - 1 ) ^{2}})

tangent f(x)=6cos(x)+3sin(2x)

t an g e n t f (x) = 6 cos (x) + 3 sin (2 x)

y^{''}-y^'-2y=0,y(0)=2,y^'(0)=2

y^{^{''}} - y^{^{'}} - 2 y = 0, y (0) = 2, y^{^{'}} (0) = 2