(\partial)/(\partial x)(1/((x-y)))

解答

\frac{\partial}{\partial x} (\frac{1}{( x - y )})

- \frac{1}{( x - y ) ^{2}}

求解步骤

\frac{\partial}{\partial x} (\frac{1}{( x - y )})

将

y

视为常数

使用指数法则:

\frac{1}{a} = a^{- 1}

= \frac{\partial}{\partial x} ((x - y)^{- 1})

使用连锁律:

- \frac{1}{( x - y ) ^{2}} \frac{\partial}{\partial x} (x - y)

= - \frac{1}{( x - y ) ^{2}} \frac{\partial}{\partial x} (x - y)

\frac{\partial}{\partial x} (x - y) = 1

= - \frac{1}{( x - y ) ^{2}} \cdot 1

化简

= - \frac{1}{( x - y ) ^{2}}

\int e^{x + 9 e^{x}} d x

a re a y = 2 x^{\frac{1}{3}}, 0 \leq x \leq 32

4 (3 x + y - 2) d x - (3 x + y) d y = 0

\frac{d}{d x} (arcsin (x) - 1 - x^{2})

y^{^{'}} = \frac{- y}{40 - t}