What is the solution for xy^'+y=50sqrt(x) ?

The solution for xy^'+y=50sqrt(x) is y=(100x^{1/2})/3+(c_{1})/x

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xy^'+y=50sqrt(x)

x y^{^{'}} + y = 50 x

y = \frac{100 x ^{\frac{1}{2}}}{3} + \frac{c _{1}}{x}

Solution steps

x y^{'} (x) + y = 50 x

Solve linear ODE:

y = \frac{100 x ^{\frac{1}{2}}}{3} + \frac{c _{1}}{x}

y = \frac{100 x ^{\frac{1}{2}}}{3} + \frac{c _{1}}{x}

f (x) = \frac{8 x}{e ^{x}}

\frac{d x}{d t} = 5 x (7 - x)

cos (x + y) d y = sin (x + y) d x

\int \frac{1}{( 625 + x ^{2} ) ^{\frac{3}{2}}} d x

\int 2 + 2 cos (θ) d θ

What is the solution for xy^'+y=50sqrt(x) ?
The solution for xy^'+y=50sqrt(x) is y=(100x^{1/2})/3+(c_{1})/x