4t(dy)/(dt)+y=t^2

Lösung

4 t \frac{d y}{d t} + y = t^{2}

y = \frac{t ^{2}}{9} + \frac{c _{1}}{4 t}

Schritte zur Lösung

4 t \frac{d y}{d t} + y = t^{2}

Solve linear ODE:

y = \frac{t ^{2}}{9} + \frac{c _{1}}{4 t}

y = \frac{t ^{2}}{9} + \frac{c _{1}}{4 t}

d er i v a t i v e f (x) = 72 x^{3} (3 x^{4} + 7)^{5}

d er i v a t i v e f (x) = \frac{x}{4 x + 5}

n = 1 \sum \infty \frac{8}{n ^{3}}

\frac{d}{d x} (1 - 3 x^{2} + y^{2})

\int sec^{3} (π) x d x