What is the derivative of x^3-6x^2+9x ?

The derivative of x^3-6x^2+9x is 3x^2-12x+9

What is the first derivative of x^3-6x^2+9x ?

The first derivative of x^3-6x^2+9x is 3x^2-12x+9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{3} - 6 x^{2} + 9 x)

3 x^{2} - 12 x + 9

Solution steps

\frac{d}{d x} (x^{3} - 6 x^{2} + 9 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (9 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (9 x) = 9

= 3 x^{2} - 12 x + 9

\frac{d}{d x} (3 cos (2 x) + ln (3 x))

\frac{d}{d x} (\frac{1 + csc ( x ^{8} )}{1 - cot ( x ^{8} )})

y^{^{'}} - y sin (x) = 2 sin (x)

\frac{\partial}{\partial x} (sin (z^{3}) cos (x y))

\int \frac{x}{( x ^{2} + 4 x + 5 ) ^{2}} d x

What is the derivative of x^3-6x^2+9x ?
The derivative of x^3-6x^2+9x is 3x^2-12x+9
What is the first derivative of x^3-6x^2+9x ?
The first derivative of x^3-6x^2+9x is 3x^2-12x+9