derivative sin(e^{-2q})

解答

导数

sin (e^{- 2 q})

- 2 e^{- 2 q} cos (e^{- 2 q})

求解步骤

\frac{d}{d q} (sin (e^{- 2 q}))

使用连锁律:

cos (e^{- 2 q}) \frac{d}{d q} (e^{- 2 q})

= cos (e^{- 2 q}) \frac{d}{d q} (e^{- 2 q})

\frac{d}{d q} (e^{- 2 q}) = - 2 e^{- 2 q}

= cos (e^{- 2 q}) (- 2 e^{- 2 q})

化简

= - 2 e^{- 2 q} cos (e^{- 2 q})

\int (cos^{2} (2 x)) d x

\frac{\partial}{\partial y} (x^{2} y e^{x})

s l o p e (0) (2.6)

n = 1 \sum \infty 4 (\frac{1}{4})^{n}

\frac{\partial}{\partial z} (z^{2} + x^{2})