f^'(x)=(x^2)/(x+1)

Lösung

f^{^{'}} (x) = \frac{x ^{2}}{x + 1}

f (x) = \frac{( x + 1 ) ^{2}}{2} - 2 (x + 1) + ln (x + 1) + c_{1}

Schritte zur Lösung

f^{'} (x) = \frac{x ^{2}}{x + 1}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

f (x) = \int \frac{x ^{2}}{x + 1} d x

\int \frac{x ^{2}}{x + 1} d x = \frac{( x + 1 ) ^{2}}{2} - 2 (x + 1) + ln (x + 1) + c_{1}

f (x) = \frac{( x + 1 ) ^{2}}{2} - 2 (x + 1) + ln (x + 1) + c_{1}

s l o p e (- 4, 1), (- 7, - 5)

x y + \frac{d y}{d x} = 120 x

\int ln (6 - 3 x) d x

2 y^{^{''}} - 5 y^{^{'}} + 6 y = 0

in v erse l a pl a ce \frac{e ^{- s} + s}{s ^{2} + s}