y^5*(y^'-y)=e^{6x}

解答

y^{5} \cdot (y^{^{'}} - y) = e^{6 x}

y = 6 6 e^{6 x} x + c_{1} e^{6 x}, y = - 6 6 e^{6 x} x + c_{1} e^{6 x}

求解步骤

y^{5} \cdot (y^{'} (x) - y) = e^{6 x}

求解贝努力方程:

y = 6 6 e^{6 x} x + c_{1} e^{6 x}, y = - 6 6 e^{6 x} x + c_{1} e^{6 x}

y = 6 6 e^{6 x} x + c_{1} e^{6 x}, y = - 6 6 e^{6 x} x + c_{1} e^{6 x}

\frac{d y}{d x} = - \frac{2 y ^{2}}{x ^{2}}

d er i v a t i v e (x + 4 x) (x^{\frac{3}{2}} - x)

\frac{\partial}{\partial x} (x e^{- z})

\frac{\partial}{\partial x} (x^{2} ln (y))

in v erse l a pl a ce \frac{( 3 s + 3 )}{( s ^{2} ( s + 2 ) ^{3} )}