面积 y= 7/(16-x^2),[1,3]

解答

面积

y = \frac{7}{16 - x ^{2}}, [1, 3]

\frac{7 ( ln ( 7 ) - ln ( \frac{5}{4} ) + ln ( \frac{3}{4} ) )}{8}

十进制

1.25569 \dots

求解步骤

使用面积公式:

\int_{1}^{3} \frac{7}{∣ 16 - x ^{2} ∣} d x

解

\int_{1}^{3} \frac{7}{∣ 16 - x ^{2} ∣} d x : \frac{7 ( ln ( 7 ) - ln ( \frac{5}{4} ) + ln ( \frac{3}{4} ) )}{8}

面积为:

= \frac{7 ( ln ( 7 ) - ln ( \frac{5}{4} ) + ln ( \frac{3}{4} ) )}{8}

\int - sin (\frac{x}{2}) d x

\frac{\partial}{\partial y} (3 x^{2} y^{2} - 4)

n = 1 \sum \infty 8 \cdot (0.2)^{n}

x \frac{d y}{d x} = y^{2} - y, y (2) = 1

t an g e n t f (x) = (10 x - 1)^{\frac{1}{2}}, at x = 1