What is the limit as x approaches 0 of (x^2+1)/(x^2) ?

The limit as x approaches 0 of (x^2+1)/(x^2) is infinity

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limit as x approaches 0 of (x^2+1)/(x^2)

x \to 0 lim (\frac{x ^{2} + 1}{x ^{2}})

\infty

Solution steps

x \to 0 lim (\frac{x ^{2} + 1}{x ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (\frac{x ^{2} + 1}{x ^{2}}) = \infty

x \to 0 + lim (\frac{x ^{2} + 1}{x ^{2}}) = \infty

= \infty

y = \frac{1}{x ( 8 + ln ( x ) )}

x y^{^{'}} + y = - 3 x y^{2}

\int e^{- 3 x} cos (2 x) d x

(5 x + 2) + (5 y - 5) y^{^{'}} = 0

\frac{4 x}{x ^{2} + 1} (1.1)

What is the limit as x approaches 0 of (x^2+1)/(x^2) ?
The limit as x approaches 0 of (x^2+1)/(x^2) is infinity