What is the derivative of e^{(x^2+x}) ?

The derivative of e^{(x^2+x}) is e^{x^2+x}(2x+1)

What is the first derivative of e^{(x^2+x}) ?

The first derivative of e^{(x^2+x}) is e^{x^2+x}(2x+1)

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\frac{d}{d x} (e^{(x^{2} + x)})

e^{x^{2} + x} (2 x + 1)

Solution steps

\frac{d}{d x} (e^{(x^{2} + x)})

Apply the chain rule:

e^{x^{2} + x} \frac{d}{d x} (x^{2} + x)

= e^{x^{2} + x} \frac{d}{d x} (x^{2} + x)

\frac{d}{d x} (x^{2} + x) = 2 x + 1

= e^{x^{2} + x} (2 x + 1)

x \to 3 lim (4 x^{2} + 1)

x^{2} + 9

n = 1 \sum \infty \frac{1}{9 n + 3 n - 2}

\frac{x + 7}{x - 7}

\frac{( 2 x + 1 )}{x ^{3}}

What is the derivative of e^{(x^2+x}) ?
The derivative of e^{(x^2+x}) is e^{x^2+x}(2x+1)
What is the first derivative of e^{(x^2+x}) ?
The first derivative of e^{(x^2+x}) is e^{x^2+x}(2x+1)