What is inverse oflaplace 4/(s^4) ?

The answer to inverse oflaplace 4/(s^4) is (2t^3)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse oflaplace 4/(s^4)

inverse laplace

\frac{4}{s ^{4}}

\frac{2 t ^{3}}{3}

Solution steps

L^{- 1} {\frac{4}{s ^{4}}}

= L^{- 1} {\frac{2}{3} \cdot \frac{6}{s ^{4}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= \frac{2}{3} L^{- 1} {\frac{6}{s ^{4}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{( n ) !}{s ^{n + 1}}} = t^{n}

L^{- 1} {\frac{6}{s ^{4}}} = t^{3}

= \frac{2}{3} t^{3}

= \frac{2 t ^{3}}{3}

\int x^{7} e^{3 x^{4}} d x

d er i v a t i v e \frac{t - t}{t ^{\frac{1}{9}}}

\frac{d}{d x} (2 x^{4} - 6 x^{3} - 12 x - 8)

n = 5 \sum \infty \frac{1}{n ( n - 1 )}

\int_{2}^{4} (x^{4} - 1) d x

What is inverse oflaplace 4/(s^4) ?
The answer to inverse oflaplace 4/(s^4) is (2t^3)/3