What is the sum from i=2 to infinity of 5/(i^2+i-2) ?

The sum from i=2 to infinity of 5/(i^2+i-2) is converges

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sum from i=2 to infinity of 5/(i^2+i-2)

i = 2 \sum \infty \frac{5}{i ^{2} + i - 2}

converges

Solution steps

i = 2 \sum \infty \frac{5}{i ^{2} + i - 2}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot i = 2 \sum \infty \frac{1}{i ^{2} + i - 2}

Apply Series Integral Test:

converges

= 5 converges

= converges

x \to 5 lim (2 x + 3)

3 \cdot cos^{2} (t)

x^{^{'}} = 0.0333333 x (30 - x)

x \to - 1 lim (\frac{x ^{2} - 5}{x + 6})

x \to 0 lim ((x + π) csc (x))

What is the sum from i=2 to infinity of 5/(i^2+i-2) ?
The sum from i=2 to infinity of 5/(i^2+i-2) is converges