zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的微积分 >

tangent 12x^2-8x-4

解答

切线

12 x^{2} - 8 x - 4

解答

y = (24 a_{0} - 8) x - 12 a_{0}^{2} - 4

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, 12 a_{0}^{2} - 8 a_{0} - 4)

计算

y = 12 x^{2} - 8 x - 4

的斜率:

\frac{d y}{d x} = 24 x - 8

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 24 a_{0} - 8

找到斜率 m=

24 a_{0} - 8

且穿过

(a_{0}, 12 a_{0}^{2} - 8 a_{0} - 4)

的直线:

y = (24 a_{0} - 8) x - 12 a_{0}^{2} - 4

y = (24 a_{0} - 8) x - 12 a_{0}^{2} - 4

作图

流行的例子

y^{''}-4y^'-12y=sin(2x)

y^{^{''}} - 4 y^{^{'}} - 12 y = sin (2 x)

tangent f(x)= 2/(x-2),\at x=-4

t an g e n t f (x) = \frac{2}{x - 2}, at x = - 4

limit as x approaches 0 of (cos(x)-x)/x

x \to 0 lim (\frac{cos ( x ) - x}{x})

面积 y=x^3,y=x^{1/2}

a re a y = x^{3}, y = x^{\frac{1}{2}}

(\partial)/(\partial x)(x^3+4x^2+x^4+3x^5)

\frac{\partial}{\partial x} (x^{3} + 4 x^{2} + x^{4} + 3 x^{5})