d/(d{x)}((8{x)/y {z}}{({x}^2+1)^2})

解

\frac{d}{d x} (\frac{8 x y z}{( x ^{2} + 1 ) ^{2}})

\frac{8 ( - 3 x ^{2} + 1 ) y z}{( x ^{2} + 1 ) ^{3}}

解答ステップ

\frac{d}{d x} (\frac{8 x y z}{( x ^{2} + 1 ) ^{2}})

定数を除去:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 y z \frac{d}{d x} (\frac{x}{( x ^{2} + 1 ) ^{2}})

商の法則を適用:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 8 y z \frac{\frac{d}{d x} ( x ) ( x ^{2} + 1 ) ^{2} - \frac{d}{d x} ( ( x ^{2} + 1 ) ^{2} ) x}{( ( x ^{2} + 1 ) ^{2} ) ^{2}}

\frac{d}{d x} (x) = 1

\frac{d}{d x} ((x^{2} + 1)^{2}) = 4 x (x^{2} + 1)

= 8 y z \frac{1 \cdot ( x ^{2} + 1 ) ^{2} - 4 x ( x ^{2} + 1 ) x}{( ( x ^{2} + 1 ) ^{2} ) ^{2}}

簡素化

8 y z \frac{1 \cdot ( x ^{2} + 1 ) ^{2} - 4 x ( x ^{2} + 1 ) x}{( ( x ^{2} + 1 ) ^{2} ) ^{2}} : \frac{8 ( - 3 x ^{2} + 1 ) y z}{( x ^{2} + 1 ) ^{3}}

= \frac{8 ( - 3 x ^{2} + 1 ) y z}{( x ^{2} + 1 ) ^{3}}