integral from 0 to 1 of 1/(x^{0.5)}

Lösung

\int_{0}^{1} \frac{1}{x ^{0.5}} d x

2

Schritte zur Lösung

\int_{0}^{1} \frac{1}{x ^{0.5}} d x

Wende die Potenzregel an

= [2 x^{0.5}]_{0}^{1}

Wende Radikal Regel an:

a^{\frac{1}{n}} = n a

= [2 x]_{0}^{1}

Berechne die Grenzen:

2

= 2

\frac{\partial}{\partial x} ((3 x + 1) y)

\int \frac{( x ^{2} + 1 )}{( x - 4 ) ( x - 3 ) ^{2}} d x

y^{^{''}} - 10 y^{^{'}} + 34 y = 0, y (0) = - 2, y^{^{'}} (0) = - 3

a re a \frac{3}{x}, \frac{3}{x ^{2}}, 6

a re a y = 5, y = x^{2} + 1