What is the integral of 1/(3+\sqrt[3]{2t^2)} ?

The integral of 1/(3+\sqrt[3]{2t^2)} is Undefined

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 1/(3+\sqrt[3]{2t^2)}

\int \frac{1}{3 + 3 2 t ^{2}} d t

Undefined

Solution steps

\int \frac{1}{3 + 3 2 t ^{2}} d t

Apply Integral Substitution

= \int 0 d u

Integral of a constant:

\int a d x = a x

= 0 \cdot u

Substitute back

u = arctan (\frac{2}{0} t)

= 0 \cdot arctan (\frac{2}{0} t)

\frac{x}{0}

is undefined

= Undefined

d er i v a t i v e x^{3} (x - 6)^{2}

\int x ln (x^{3}) d x

\frac{\partial}{\partial x} (\frac{2 x - y}{x + 4 y})

d er i v a t i v e (x - 3)^{- 2}

\frac{d y}{d x} = \frac{e ^{x}}{y ^{2}}

What is the integral of 1/(3+\sqrt[3]{2t^2)} ?
The integral of 1/(3+\sqrt[3]{2t^2)} is Undefined